This shows you the differences between two versions of the page.
| Both sides previous revision Previous revision Next revision | Previous revision | ||
|
transfer_matrix [2021/04/29 19:59] Scott Lawrence [Transfer matrix] |
transfer_matrix [2021/04/29 20:03] (current) Scott Lawrence [Transfer matrix] |
||
|---|---|---|---|
| Line 11: | Line 11: | ||
| Z(\beta) = \operatorname{Tr} e^{-\beta H} | Z(\beta) = \operatorname{Tr} e^{-\beta H} | ||
| = \operatorname{Tr} \left(e^{-\beta H / N}\right)^N | = \operatorname{Tr} \left(e^{-\beta H / N}\right)^N | ||
| - | = \sum_{s_1, | + | = \sum_{s_1, |
| \end{equation} | \end{equation} | ||
| + | Here we have introduced $T \equiv e^{-\beta H / N}$, the transfer matrix. The final expression has the form of a path integral, as $\langle s' | T | s \rangle$ can be written $e^{-J s' s}$ for some $J$ (a function of $\mu$). As a result, we have derived a Euclidean action of the form | ||
| + | \begin{equation} | ||
| + | S = -J \sum_{\langle i j \rangle} s_i s_j\text, | ||
| + | \end{equation} | ||
| + | and we see that the two-level system lets us solve the one-dimensional Ising model! | ||
| This story can be told in reverse, where we start from an apparently difficult high-dimensional integral (like the Ising model in one dimension), and reduce it to a low-dimension matrix by expressing it in terms of a transfer matrix. | This story can be told in reverse, where we start from an apparently difficult high-dimensional integral (like the Ising model in one dimension), and reduce it to a low-dimension matrix by expressing it in terms of a transfer matrix. | ||